7(t+3)=2(t-9)+2t

Solution for 7(t+3)=2(t-9)+2t equation:

7(t+3)=2(t-9)+2t

We move all terms to the left:

7(t+3)-(2(t-9)+2t)=0

We multiply parentheses

7t-(2(t-9)+2t)+21=0


We calculate terms in parentheses: -(2(t-9)+2t), so:

2(t-9)+2t

We add all the numbers together, and all the variables

2t+2(t-9)

We multiply parentheses

2t+2t-18

We add all the numbers together, and all the variables

4t-18

Back to the equation:

-(4t-18)


We get rid of parentheses

7t-4t+18+21=0

We add all the numbers together, and all the variables

3t+39=0

We move all terms containing t to the left, all other terms to the right

3t=-39

t=-39/3

t=-13