7(t+4)=2(t-3)

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Solution for 7(t+4)=2(t-3) equation: 



7(t+4)=2(t-3)

We move all terms to the left:

7(t+4)-(2(t-3))=0

We multiply parentheses

7t-(2(t-3))+28=0



We calculate terms in parentheses: -(2(t-3)), so:

2(t-3)

We multiply parentheses

2t-6

Back to the equation:

-(2t-6)



We get rid of parentheses

7t-2t+6+28=0

We add all the numbers together, and all the variables

5t+34=0

We move all terms containing t to the left, all other terms to the right

5t=-34

t=-34/5

t=-6+4/5

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