7(t-2)+3t=5(2t+3)-13

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Solution for 7(t-2)+3t=5(2t+3)-13 equation:


Simplifying
7(t + -2) + 3t = 5(2t + 3) + -13

Reorder the terms:
7(-2 + t) + 3t = 5(2t + 3) + -13
(-2 * 7 + t * 7) + 3t = 5(2t + 3) + -13
(-14 + 7t) + 3t = 5(2t + 3) + -13

Combine like terms: 7t + 3t = 10t
-14 + 10t = 5(2t + 3) + -13

Reorder the terms:
-14 + 10t = 5(3 + 2t) + -13
-14 + 10t = (3 * 5 + 2t * 5) + -13
-14 + 10t = (15 + 10t) + -13

Reorder the terms:
-14 + 10t = 15 + -13 + 10t

Combine like terms: 15 + -13 = 2
-14 + 10t = 2 + 10t

Add '-10t' to each side of the equation.
-14 + 10t + -10t = 2 + 10t + -10t

Combine like terms: 10t + -10t = 0
-14 + 0 = 2 + 10t + -10t
-14 = 2 + 10t + -10t

Combine like terms: 10t + -10t = 0
-14 = 2 + 0
-14 = 2

Solving
-14 = 2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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