7(t-2)+4=2(2t+1)+3

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Solution for 7(t-2)+4=2(2t+1)+3 equation: 



7(t-2)+4=2(2t+1)+3

We move all terms to the left:

7(t-2)+4-(2(2t+1)+3)=0

We multiply parentheses

7t-(2(2t+1)+3)-14+4=0



We calculate terms in parentheses: -(2(2t+1)+3), so:

2(2t+1)+3

We multiply parentheses

4t+2+3

We add all the numbers together, and all the variables

4t+5

Back to the equation:

-(4t+5)



We add all the numbers together, and all the variables

7t-(4t+5)-10=0

We get rid of parentheses

7t-4t-5-10=0

We add all the numbers together, and all the variables

3t-15=0

We move all terms containing t to the left, all other terms to the right

3t=15

t=15/3

t=5

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