7(t-2)+5t=4(3t+4)-13

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Solution for 7(t-2)+5t=4(3t+4)-13 equation: 



7(t-2)+5t=4(3t+4)-13

We move all terms to the left:

7(t-2)+5t-(4(3t+4)-13)=0

We add all the numbers together, and all the variables

5t+7(t-2)-(4(3t+4)-13)=0

We multiply parentheses

5t+7t-(4(3t+4)-13)-14=0



We calculate terms in parentheses: -(4(3t+4)-13), so:

4(3t+4)-13

We multiply parentheses

12t+16-13

We add all the numbers together, and all the variables

12t+3

Back to the equation:

-(12t+3)



We add all the numbers together, and all the variables

12t-(12t+3)-14=0

We get rid of parentheses

12t-12t-3-14=0

We add all the numbers together, and all the variables

-17!=0

There is no solution for this equation

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