7(t-2)+7=2(2t+2)+1

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Solution for 7(t-2)+7=2(2t+2)+1 equation: 



7(t-2)+7=2(2t+2)+1

We move all terms to the left:

7(t-2)+7-(2(2t+2)+1)=0

We multiply parentheses

7t-(2(2t+2)+1)-14+7=0



We calculate terms in parentheses: -(2(2t+2)+1), so:

2(2t+2)+1

We multiply parentheses

4t+4+1

We add all the numbers together, and all the variables

4t+5

Back to the equation:

-(4t+5)



We add all the numbers together, and all the variables

7t-(4t+5)-7=0

We get rid of parentheses

7t-4t-5-7=0

We add all the numbers together, and all the variables

3t-12=0

We move all terms containing t to the left, all other terms to the right

3t=12

t=12/3

t=4

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