7(t-3)+4t+2-2t=3(t+5)-4t

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Solution for 7(t-3)+4t+2-2t=3(t+5)-4t equation: 



7(t-3)+4t+2-2t=3(t+5)-4t

We move all terms to the left:

7(t-3)+4t+2-2t-(3(t+5)-4t)=0

We add all the numbers together, and all the variables

2t+7(t-3)-(3(t+5)-4t)+2=0

We multiply parentheses

2t+7t-(3(t+5)-4t)-21+2=0



We calculate terms in parentheses: -(3(t+5)-4t), so:

3(t+5)-4t

We add all the numbers together, and all the variables

-4t+3(t+5)

We multiply parentheses

-4t+3t+15

We add all the numbers together, and all the variables

-1t+15

Back to the equation:

-(-1t+15)



We add all the numbers together, and all the variables

9t-(-1t+15)-19=0

We get rid of parentheses

9t+1t-15-19=0

We add all the numbers together, and all the variables

10t-34=0

We move all terms containing t to the left, all other terms to the right

10t=34

t=34/10

t=3+2/5

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