7(t-3)+8=5(3t+2)-8

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Solution for 7(t-3)+8=5(3t+2)-8 equation: 



7(t-3)+8=5(3t+2)-8

We move all terms to the left:

7(t-3)+8-(5(3t+2)-8)=0

We multiply parentheses

7t-(5(3t+2)-8)-21+8=0



We calculate terms in parentheses: -(5(3t+2)-8), so:

5(3t+2)-8

We multiply parentheses

15t+10-8

We add all the numbers together, and all the variables

15t+2

Back to the equation:

-(15t+2)



We add all the numbers together, and all the variables

7t-(15t+2)-13=0

We get rid of parentheses

7t-15t-2-13=0

We add all the numbers together, and all the variables

-8t-15=0

We move all terms containing t to the left, all other terms to the right

-8t=15

t=15/-8

t=-1+7/8

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