7(t-4)+3t=5(2t+4)-13

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Solution for 7(t-4)+3t=5(2t+4)-13 equation:


Simplifying
7(t + -4) + 3t = 5(2t + 4) + -13

Reorder the terms:
7(-4 + t) + 3t = 5(2t + 4) + -13
(-4 * 7 + t * 7) + 3t = 5(2t + 4) + -13
(-28 + 7t) + 3t = 5(2t + 4) + -13

Combine like terms: 7t + 3t = 10t
-28 + 10t = 5(2t + 4) + -13

Reorder the terms:
-28 + 10t = 5(4 + 2t) + -13
-28 + 10t = (4 * 5 + 2t * 5) + -13
-28 + 10t = (20 + 10t) + -13

Reorder the terms:
-28 + 10t = 20 + -13 + 10t

Combine like terms: 20 + -13 = 7
-28 + 10t = 7 + 10t

Add '-10t' to each side of the equation.
-28 + 10t + -10t = 7 + 10t + -10t

Combine like terms: 10t + -10t = 0
-28 + 0 = 7 + 10t + -10t
-28 = 7 + 10t + -10t

Combine like terms: 10t + -10t = 0
-28 = 7 + 0
-28 = 7

Solving
-28 = 7

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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