7(t-4)+3t=5(2t+4)-8

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Solution for 7(t-4)+3t=5(2t+4)-8 equation: 


Simplifying
7(t + -4) + 3t = 5(2t + 4) + -8

Reorder the terms:
7(-4 + t) + 3t = 5(2t + 4) + -8
(-4 * 7 + t * 7) + 3t = 5(2t + 4) + -8
(-28 + 7t) + 3t = 5(2t + 4) + -8

Combine like terms: 7t + 3t = 10t
-28 + 10t = 5(2t + 4) + -8

Reorder the terms:
-28 + 10t = 5(4 + 2t) + -8
-28 + 10t = (4 * 5 + 2t * 5) + -8
-28 + 10t = (20 + 10t) + -8

Reorder the terms:
-28 + 10t = 20 + -8 + 10t

Combine like terms: 20 + -8 = 12
-28 + 10t = 12 + 10t

Add '-10t' to each side of the equation.
-28 + 10t + -10t = 12 + 10t + -10t

Combine like terms: 10t + -10t = 0
-28 + 0 = 12 + 10t + -10t
-28 = 12 + 10t + -10t

Combine like terms: 10t + -10t = 0
-28 = 12 + 0
-28 = 12

Solving
-28 = 12

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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