7(t-4)+5t=6(2t+2)-10

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Solution for 7(t-4)+5t=6(2t+2)-10 equation:


Simplifying
7(t + -4) + 5t = 6(2t + 2) + -10

Reorder the terms:
7(-4 + t) + 5t = 6(2t + 2) + -10
(-4 * 7 + t * 7) + 5t = 6(2t + 2) + -10
(-28 + 7t) + 5t = 6(2t + 2) + -10

Combine like terms: 7t + 5t = 12t
-28 + 12t = 6(2t + 2) + -10

Reorder the terms:
-28 + 12t = 6(2 + 2t) + -10
-28 + 12t = (2 * 6 + 2t * 6) + -10
-28 + 12t = (12 + 12t) + -10

Reorder the terms:
-28 + 12t = 12 + -10 + 12t

Combine like terms: 12 + -10 = 2
-28 + 12t = 2 + 12t

Add '-12t' to each side of the equation.
-28 + 12t + -12t = 2 + 12t + -12t

Combine like terms: 12t + -12t = 0
-28 + 0 = 2 + 12t + -12t
-28 = 2 + 12t + -12t

Combine like terms: 12t + -12t = 0
-28 = 2 + 0
-28 = 2

Solving
-28 = 2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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