7(t-4)+7t=7(2t+3)-8

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Solution for 7(t-4)+7t=7(2t+3)-8 equation:


Simplifying
7(t + -4) + 7t = 7(2t + 3) + -8

Reorder the terms:
7(-4 + t) + 7t = 7(2t + 3) + -8
(-4 * 7 + t * 7) + 7t = 7(2t + 3) + -8
(-28 + 7t) + 7t = 7(2t + 3) + -8

Combine like terms: 7t + 7t = 14t
-28 + 14t = 7(2t + 3) + -8

Reorder the terms:
-28 + 14t = 7(3 + 2t) + -8
-28 + 14t = (3 * 7 + 2t * 7) + -8
-28 + 14t = (21 + 14t) + -8

Reorder the terms:
-28 + 14t = 21 + -8 + 14t

Combine like terms: 21 + -8 = 13
-28 + 14t = 13 + 14t

Add '-14t' to each side of the equation.
-28 + 14t + -14t = 13 + 14t + -14t

Combine like terms: 14t + -14t = 0
-28 + 0 = 13 + 14t + -14t
-28 = 13 + 14t + -14t

Combine like terms: 14t + -14t = 0
-28 = 13 + 0
-28 = 13

Solving
-28 = 13

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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