7(t-5)+3t=5(2t+3)-12

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Solution for 7(t-5)+3t=5(2t+3)-12 equation:


Simplifying
7(t + -5) + 3t = 5(2t + 3) + -12

Reorder the terms:
7(-5 + t) + 3t = 5(2t + 3) + -12
(-5 * 7 + t * 7) + 3t = 5(2t + 3) + -12
(-35 + 7t) + 3t = 5(2t + 3) + -12

Combine like terms: 7t + 3t = 10t
-35 + 10t = 5(2t + 3) + -12

Reorder the terms:
-35 + 10t = 5(3 + 2t) + -12
-35 + 10t = (3 * 5 + 2t * 5) + -12
-35 + 10t = (15 + 10t) + -12

Reorder the terms:
-35 + 10t = 15 + -12 + 10t

Combine like terms: 15 + -12 = 3
-35 + 10t = 3 + 10t

Add '-10t' to each side of the equation.
-35 + 10t + -10t = 3 + 10t + -10t

Combine like terms: 10t + -10t = 0
-35 + 0 = 3 + 10t + -10t
-35 = 3 + 10t + -10t

Combine like terms: 10t + -10t = 0
-35 = 3 + 0
-35 = 3

Solving
-35 = 3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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