7(t-5)+3t=5(2t+4)-10

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Solution for 7(t-5)+3t=5(2t+4)-10 equation: 


Simplifying
7(t + -5) + 3t = 5(2t + 4) + -10

Reorder the terms:
7(-5 + t) + 3t = 5(2t + 4) + -10
(-5 * 7 + t * 7) + 3t = 5(2t + 4) + -10
(-35 + 7t) + 3t = 5(2t + 4) + -10

Combine like terms: 7t + 3t = 10t
-35 + 10t = 5(2t + 4) + -10

Reorder the terms:
-35 + 10t = 5(4 + 2t) + -10
-35 + 10t = (4 * 5 + 2t * 5) + -10
-35 + 10t = (20 + 10t) + -10

Reorder the terms:
-35 + 10t = 20 + -10 + 10t

Combine like terms: 20 + -10 = 10
-35 + 10t = 10 + 10t

Add '-10t' to each side of the equation.
-35 + 10t + -10t = 10 + 10t + -10t

Combine like terms: 10t + -10t = 0
-35 + 0 = 10 + 10t + -10t
-35 = 10 + 10t + -10t

Combine like terms: 10t + -10t = 0
-35 = 10 + 0
-35 = 10

Solving
-35 = 10

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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