7(t-5)+5t=6(2t+3)-11

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Solution for 7(t-5)+5t=6(2t+3)-11 equation: 



7(t-5)+5t=6(2t+3)-11

We move all terms to the left:

7(t-5)+5t-(6(2t+3)-11)=0

We add all the numbers together, and all the variables

5t+7(t-5)-(6(2t+3)-11)=0

We multiply parentheses

5t+7t-(6(2t+3)-11)-35=0



We calculate terms in parentheses: -(6(2t+3)-11), so:

6(2t+3)-11

We multiply parentheses

12t+18-11

We add all the numbers together, and all the variables

12t+7

Back to the equation:

-(12t+7)



We add all the numbers together, and all the variables

12t-(12t+7)-35=0

We get rid of parentheses

12t-12t-7-35=0

We add all the numbers together, and all the variables

-42!=0

There is no solution for this equation

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