7(t-5)+5t=6(2t+3)-12

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Solution for 7(t-5)+5t=6(2t+3)-12 equation: 



7(t-5)+5t=6(2t+3)-12

We move all terms to the left:

7(t-5)+5t-(6(2t+3)-12)=0

We add all the numbers together, and all the variables

5t+7(t-5)-(6(2t+3)-12)=0

We multiply parentheses

5t+7t-(6(2t+3)-12)-35=0



We calculate terms in parentheses: -(6(2t+3)-12), so:

6(2t+3)-12

We multiply parentheses

12t+18-12

We add all the numbers together, and all the variables

12t+6

Back to the equation:

-(12t+6)



We add all the numbers together, and all the variables

12t-(12t+6)-35=0

We get rid of parentheses

12t-12t-6-35=0

We add all the numbers together, and all the variables

-41!=0

There is no solution for this equation

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