7(u+1)=2u-33

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Solution for 7(u+1)=2u-33 equation: 



7(u+1)=2u-33

We move all terms to the left:

7(u+1)-(2u-33)=0

We multiply parentheses

7u-(2u-33)+7=0

We get rid of parentheses

7u-2u+33+7=0

We add all the numbers together, and all the variables

5u+40=0

We move all terms containing u to the left, all other terms to the right

5u=-40

u=-40/5

u=-8

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