7(u+3)=-5(2u-5)+7u

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Solution for 7(u+3)=-5(2u-5)+7u equation: 



7(u+3)=-5(2u-5)+7u

We move all terms to the left:

7(u+3)-(-5(2u-5)+7u)=0

We multiply parentheses

7u-(-5(2u-5)+7u)+21=0



We calculate terms in parentheses: -(-5(2u-5)+7u), so:

-5(2u-5)+7u

We add all the numbers together, and all the variables

7u-5(2u-5)

We multiply parentheses

7u-10u+25

We add all the numbers together, and all the variables

-3u+25

Back to the equation:

-(-3u+25)



We get rid of parentheses

7u+3u-25+21=0

We add all the numbers together, and all the variables

10u-4=0

We move all terms containing u to the left, all other terms to the right

10u=4

u=4/10

u=2/5

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