7(u-1)-3=-3(-7u+2)-6u

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Solution for 7(u-1)-3=-3(-7u+2)-6u equation: 



7(u-1)-3=-3(-7u+2)-6u

We move all terms to the left:

7(u-1)-3-(-3(-7u+2)-6u)=0

We multiply parentheses

7u-(-3(-7u+2)-6u)-7-3=0



We calculate terms in parentheses: -(-3(-7u+2)-6u), so:

-3(-7u+2)-6u

We add all the numbers together, and all the variables

-6u-3(-7u+2)

We multiply parentheses

-6u+21u-6

We add all the numbers together, and all the variables

15u-6

Back to the equation:

-(15u-6)



We add all the numbers together, and all the variables

7u-(15u-6)-10=0

We get rid of parentheses

7u-15u+6-10=0

We add all the numbers together, and all the variables

-8u-4=0

We move all terms containing u to the left, all other terms to the right

-8u=4

u=4/-8

u=-1/2

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