7(u-2)-3=-3(-8u+4)-2u

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Solution for 7(u-2)-3=-3(-8u+4)-2u equation: 



7(u-2)-3=-3(-8u+4)-2u

We move all terms to the left:

7(u-2)-3-(-3(-8u+4)-2u)=0

We multiply parentheses

7u-(-3(-8u+4)-2u)-14-3=0



We calculate terms in parentheses: -(-3(-8u+4)-2u), so:

-3(-8u+4)-2u

We add all the numbers together, and all the variables

-2u-3(-8u+4)

We multiply parentheses

-2u+24u-12

We add all the numbers together, and all the variables

22u-12

Back to the equation:

-(22u-12)



We add all the numbers together, and all the variables

7u-(22u-12)-17=0

We get rid of parentheses

7u-22u+12-17=0

We add all the numbers together, and all the variables

-15u-5=0

We move all terms containing u to the left, all other terms to the right

-15u=5

u=5/-15

u=-1/3

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