7(u-3)-8=-5(-4u+5)-3u

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Solution for 7(u-3)-8=-5(-4u+5)-3u equation: 



7(u-3)-8=-5(-4u+5)-3u

We move all terms to the left:

7(u-3)-8-(-5(-4u+5)-3u)=0

We multiply parentheses

7u-(-5(-4u+5)-3u)-21-8=0



We calculate terms in parentheses: -(-5(-4u+5)-3u), so:

-5(-4u+5)-3u

We add all the numbers together, and all the variables

-3u-5(-4u+5)

We multiply parentheses

-3u+20u-25

We add all the numbers together, and all the variables

17u-25

Back to the equation:

-(17u-25)



We add all the numbers together, and all the variables

7u-(17u-25)-29=0

We get rid of parentheses

7u-17u+25-29=0

We add all the numbers together, and all the variables

-10u-4=0

We move all terms containing u to the left, all other terms to the right

-10u=4

u=4/-10

u=-2/5

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