7(u-3)=5u-41

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Solution for 7(u-3)=5u-41 equation: 



7(u-3)=5u-41

We move all terms to the left:

7(u-3)-(5u-41)=0

We multiply parentheses

7u-(5u-41)-21=0

We get rid of parentheses

7u-5u+41-21=0

We add all the numbers together, and all the variables

2u+20=0

We move all terms containing u to the left, all other terms to the right

2u=-20

u=-20/2

u=-10

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