7(u-6)=4u-33

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Solution for 7(u-6)=4u-33 equation: 



7(u-6)=4u-33

We move all terms to the left:

7(u-6)-(4u-33)=0

We multiply parentheses

7u-(4u-33)-42=0

We get rid of parentheses

7u-4u+33-42=0

We add all the numbers together, and all the variables

3u-9=0

We move all terms containing u to the left, all other terms to the right

3u=9

u=9/3

u=3

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