7(v+2)-3v=2(2v+2)-5

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Solution for 7(v+2)-3v=2(2v+2)-5 equation:



7(v+2)-3v=2(2v+2)-5
We move all terms to the left:
7(v+2)-3v-(2(2v+2)-5)=0
We add all the numbers together, and all the variables
-3v+7(v+2)-(2(2v+2)-5)=0
We multiply parentheses
-3v+7v-(2(2v+2)-5)+14=0
We calculate terms in parentheses: -(2(2v+2)-5), so:
2(2v+2)-5
We multiply parentheses
4v+4-5
We add all the numbers together, and all the variables
4v-1
Back to the equation:
-(4v-1)
We add all the numbers together, and all the variables
4v-(4v-1)+14=0
We get rid of parentheses
4v-4v+1+14=0
We add all the numbers together, and all the variables
15!=0
There is no solution for this equation

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