7(v+2)=-3(3v-4)+4v

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Solution for 7(v+2)=-3(3v-4)+4v equation: 



7(v+2)=-3(3v-4)+4v

We move all terms to the left:

7(v+2)-(-3(3v-4)+4v)=0

We multiply parentheses

7v-(-3(3v-4)+4v)+14=0



We calculate terms in parentheses: -(-3(3v-4)+4v), so:

-3(3v-4)+4v

We add all the numbers together, and all the variables

4v-3(3v-4)

We multiply parentheses

4v-9v+12

We add all the numbers together, and all the variables

-5v+12

Back to the equation:

-(-5v+12)



We get rid of parentheses

7v+5v-12+14=0

We add all the numbers together, and all the variables

12v+2=0

We move all terms containing v to the left, all other terms to the right

12v=-2

v=-2/12

v=-1/6

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