7(v+4)=-4(2v-4)+5v

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Solution for 7(v+4)=-4(2v-4)+5v equation: 



7(v+4)=-4(2v-4)+5v

We move all terms to the left:

7(v+4)-(-4(2v-4)+5v)=0

We multiply parentheses

7v-(-4(2v-4)+5v)+28=0



We calculate terms in parentheses: -(-4(2v-4)+5v), so:

-4(2v-4)+5v

We add all the numbers together, and all the variables

5v-4(2v-4)

We multiply parentheses

5v-8v+16

We add all the numbers together, and all the variables

-3v+16

Back to the equation:

-(-3v+16)



We get rid of parentheses

7v+3v-16+28=0

We add all the numbers together, and all the variables

10v+12=0

We move all terms containing v to the left, all other terms to the right

10v=-12

v=-12/10

v=-1+1/5

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