7(v-1)=5v+5-2(-6v-2)

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Solution for 7(v-1)=5v+5-2(-6v-2) equation: 



7(v-1)=5v+5-2(-6v-2)

We move all terms to the left:

7(v-1)-(5v+5-2(-6v-2))=0

We multiply parentheses

7v-(5v+5-2(-6v-2))-7=0



We calculate terms in parentheses: -(5v+5-2(-6v-2)), so:

5v+5-2(-6v-2)

determiningTheFunctionDomain
5v-2(-6v-2)+5

We multiply parentheses

5v+12v+4+5

We add all the numbers together, and all the variables

17v+9

Back to the equation:

-(17v+9)



We get rid of parentheses

7v-17v-9-7=0

We add all the numbers together, and all the variables

-10v-16=0

We move all terms containing v to the left, all other terms to the right

-10v=16

v=16/-10

v=-1+3/5

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