7(v-5)=4v-32

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Solution for 7(v-5)=4v-32 equation: 



7(v-5)=4v-32

We move all terms to the left:

7(v-5)-(4v-32)=0

We multiply parentheses

7v-(4v-32)-35=0

We get rid of parentheses

7v-4v+32-35=0

We add all the numbers together, and all the variables

3v-3=0

We move all terms containing v to the left, all other terms to the right

3v=3

v=3/3

v=1

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