7(w+1)=5(2w-3)+6

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Solution for 7(w+1)=5(2w-3)+6 equation: 



7(w+1)=5(2w-3)+6

We move all terms to the left:

7(w+1)-(5(2w-3)+6)=0

We multiply parentheses

7w-(5(2w-3)+6)+7=0



We calculate terms in parentheses: -(5(2w-3)+6), so:

5(2w-3)+6

We multiply parentheses

10w-15+6

We add all the numbers together, and all the variables

10w-9

Back to the equation:

-(10w-9)



We get rid of parentheses

7w-10w+9+7=0

We add all the numbers together, and all the variables

-3w+16=0

We move all terms containing w to the left, all other terms to the right

-3w=-16

w=-16/-3

w=5+1/3

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