7(w+2)=-2(3w-5)+w

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Solution for 7(w+2)=-2(3w-5)+w equation: 



7(w+2)=-2(3w-5)+w

We move all terms to the left:

7(w+2)-(-2(3w-5)+w)=0

We multiply parentheses

7w-(-2(3w-5)+w)+14=0



We calculate terms in parentheses: -(-2(3w-5)+w), so:

-2(3w-5)+w

We add all the numbers together, and all the variables

w-2(3w-5)

We multiply parentheses

w-6w+10

We add all the numbers together, and all the variables

-5w+10

Back to the equation:

-(-5w+10)



We get rid of parentheses

7w+5w-10+14=0

We add all the numbers together, and all the variables

12w+4=0

We move all terms containing w to the left, all other terms to the right

12w=-4

w=-4/12

w=-1/3

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