7(w+4)=-6(2w-2)+w

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Solution for 7(w+4)=-6(2w-2)+w equation: 



7(w+4)=-6(2w-2)+w

We move all terms to the left:

7(w+4)-(-6(2w-2)+w)=0

We multiply parentheses

7w-(-6(2w-2)+w)+28=0



We calculate terms in parentheses: -(-6(2w-2)+w), so:

-6(2w-2)+w

We add all the numbers together, and all the variables

w-6(2w-2)

We multiply parentheses

w-12w+12

We add all the numbers together, and all the variables

-11w+12

Back to the equation:

-(-11w+12)



We get rid of parentheses

7w+11w-12+28=0

We add all the numbers together, and all the variables

18w+16=0

We move all terms containing w to the left, all other terms to the right

18w=-16

w=-16/18

w=-8/9

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