7(x+1)(x-1)=0

Solution for 7(x+1)(x-1)=0 equation:

Simplifying
7(x + 1)(x + -1) = 0

Reorder the terms:
7(1 + x)(x + -1) = 0

Reorder the terms:
7(1 + x)(-1 + x) = 0

Multiply (1 + x) * (-1 + x)
7(1(-1 + x) + x(-1 + x)) = 0
7((-1 * 1 + x * 1) + x(-1 + x)) = 0
7((-1 + 1x) + x(-1 + x)) = 0
7(-1 + 1x + (-1 * x + x * x)) = 0
7(-1 + 1x + (-1x + x2)) = 0

Combine like terms: 1x + -1x = 0
7(-1 + 0 + x2) = 0
7(-1 + x2) = 0
(-1 * 7 + x2 * 7) = 0
(-7 + 7x2) = 0

Solving
-7 + 7x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + 7x2 = 0 + 7

Combine like terms: -7 + 7 = 0
0 + 7x2 = 0 + 7
7x2 = 0 + 7

Combine like terms: 0 + 7 = 7
7x2 = 7

Divide each side by '7'.
x2 = 1

Simplifying
x2 = 1

Take the square root of each side:
x = {-1, 1}