7(x+1)+2(x+3)=4(6-3x)-5(4x+2)

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Solution for 7(x+1)+2(x+3)=4(6-3x)-5(4x+2) equation: 



7(x+1)+2(x+3)=4(6-3x)-5(4x+2)

We move all terms to the left:

7(x+1)+2(x+3)-(4(6-3x)-5(4x+2))=0

We add all the numbers together, and all the variables

7(x+1)+2(x+3)-(4(-3x+6)-5(4x+2))=0

We multiply parentheses

7x+2x-(4(-3x+6)-5(4x+2))+7+6=0



We calculate terms in parentheses: -(4(-3x+6)-5(4x+2)), so:

4(-3x+6)-5(4x+2)

We multiply parentheses

-12x-20x+24-10

We add all the numbers together, and all the variables

-32x+14

Back to the equation:

-(-32x+14)



We add all the numbers together, and all the variables

9x-(-32x+14)+13=0

We get rid of parentheses

9x+32x-14+13=0

We add all the numbers together, and all the variables

41x-1=0

We move all terms containing x to the left, all other terms to the right

41x=1

x=1/41

x=1/41

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