7(x+1)+3=-8(x-4)-7

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Solution for 7(x+1)+3=-8(x-4)-7 equation: 



7(x+1)+3=-8(x-4)-7

We move all terms to the left:

7(x+1)+3-(-8(x-4)-7)=0

We multiply parentheses

7x-(-8(x-4)-7)+7+3=0



We calculate terms in parentheses: -(-8(x-4)-7), so:

-8(x-4)-7

We multiply parentheses

-8x+32-7

We add all the numbers together, and all the variables

-8x+25

Back to the equation:

-(-8x+25)



We add all the numbers together, and all the variables

7x-(-8x+25)+10=0

We get rid of parentheses

7x+8x-25+10=0

We add all the numbers together, and all the variables

15x-15=0

We move all terms containing x to the left, all other terms to the right

15x=15

x=15/15

x=1

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