7(x+1)+3=2(x-1)-1

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Solution for 7(x+1)+3=2(x-1)-1 equation: 



7(x+1)+3=2(x-1)-1

We move all terms to the left:

7(x+1)+3-(2(x-1)-1)=0

We multiply parentheses

7x-(2(x-1)-1)+7+3=0



We calculate terms in parentheses: -(2(x-1)-1), so:

2(x-1)-1

We multiply parentheses

2x-2-1

We add all the numbers together, and all the variables

2x-3

Back to the equation:

-(2x-3)



We add all the numbers together, and all the variables

7x-(2x-3)+10=0

We get rid of parentheses

7x-2x+3+10=0

We add all the numbers together, and all the variables

5x+13=0

We move all terms containing x to the left, all other terms to the right

5x=-13

x=-13/5

x=-2+3/5

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