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7(x+1)+5=2x+5(2+x)
We move all terms to the left:
7(x+1)+5-(2x+5(2+x))=0
We add all the numbers together, and all the variables
7(x+1)-(2x+5(x+2))+5=0
We multiply parentheses
7x-(2x+5(x+2))+7+5=0
We calculate terms in parentheses: -(2x+5(x+2)), so:We add all the numbers together, and all the variables
2x+5(x+2)
We multiply parentheses
2x+5x+10
We add all the numbers together, and all the variables
7x+10
Back to the equation:
-(7x+10)
7x-(7x+10)+12=0
We get rid of parentheses
7x-7x-10+12=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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