7(x+1)+8(x+2)=-6

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Solution for 7(x+1)+8(x+2)=-6 equation: 



7(x+1)+8(x+2)=-6

We move all terms to the left:

7(x+1)+8(x+2)-(-6)=0

We add all the numbers together, and all the variables

7(x+1)+8(x+2)+6=0

We multiply parentheses

7x+8x+7+16+6=0

We add all the numbers together, and all the variables

15x+29=0

We move all terms containing x to the left, all other terms to the right

15x=-29

x=-29/15

x=-1+14/15

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