7(x+1)-3x=3(x-4)+20

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Solution for 7(x+1)-3x=3(x-4)+20 equation: 



7(x+1)-3x=3(x-4)+20

We move all terms to the left:

7(x+1)-3x-(3(x-4)+20)=0

We add all the numbers together, and all the variables

-3x+7(x+1)-(3(x-4)+20)=0

We multiply parentheses

-3x+7x-(3(x-4)+20)+7=0



We calculate terms in parentheses: -(3(x-4)+20), so:

3(x-4)+20

We multiply parentheses

3x-12+20

We add all the numbers together, and all the variables

3x+8

Back to the equation:

-(3x+8)



We add all the numbers together, and all the variables

4x-(3x+8)+7=0

We get rid of parentheses

4x-3x-8+7=0

We add all the numbers together, and all the variables

x-1=0

We move all terms containing x to the left, all other terms to the right

x=1

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