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7(x+1)-4=5x+2(1+x)
We move all terms to the left:
7(x+1)-4-(5x+2(1+x))=0
We add all the numbers together, and all the variables
7(x+1)-(5x+2(x+1))-4=0
We multiply parentheses
7x-(5x+2(x+1))+7-4=0
We calculate terms in parentheses: -(5x+2(x+1)), so:We add all the numbers together, and all the variables
5x+2(x+1)
We multiply parentheses
5x+2x+2
We add all the numbers together, and all the variables
7x+2
Back to the equation:
-(7x+2)
7x-(7x+2)+3=0
We get rid of parentheses
7x-7x-2+3=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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