7(x+1)-4x=13(3x-2)

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Solution for 7(x+1)-4x=13(3x-2) equation: 



7(x+1)-4x=13(3x-2)

We move all terms to the left:

7(x+1)-4x-(13(3x-2))=0

We add all the numbers together, and all the variables

-4x+7(x+1)-(13(3x-2))=0

We multiply parentheses

-4x+7x-(13(3x-2))+7=0



We calculate terms in parentheses: -(13(3x-2)), so:

13(3x-2)

We multiply parentheses

39x-26

Back to the equation:

-(39x-26)



We add all the numbers together, and all the variables

3x-(39x-26)+7=0

We get rid of parentheses

3x-39x+26+7=0

We add all the numbers together, and all the variables

-36x+33=0

We move all terms containing x to the left, all other terms to the right

-36x=-33

x=-33/-36

x=11/12

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