7(x+1)-5=3(x+2)+4(x+1)

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Solution for 7(x+1)-5=3(x+2)+4(x+1) equation: 



7(x+1)-5=3(x+2)+4(x+1)

We move all terms to the left:

7(x+1)-5-(3(x+2)+4(x+1))=0

We multiply parentheses

7x-(3(x+2)+4(x+1))+7-5=0



We calculate terms in parentheses: -(3(x+2)+4(x+1)), so:

3(x+2)+4(x+1)

We multiply parentheses

3x+4x+6+4

We add all the numbers together, and all the variables

7x+10

Back to the equation:

-(7x+10)



We add all the numbers together, and all the variables

7x-(7x+10)+2=0

We get rid of parentheses

7x-7x-10+2=0

We add all the numbers together, and all the variables

-8!=0

There is no solution for this equation

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