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7(x+1)-6x=5x-4(x-3)
We move all terms to the left:
7(x+1)-6x-(5x-4(x-3))=0
We add all the numbers together, and all the variables
-6x+7(x+1)-(5x-4(x-3))=0
We multiply parentheses
-6x+7x-(5x-4(x-3))+7=0
We calculate terms in parentheses: -(5x-4(x-3)), so:We add all the numbers together, and all the variables
5x-4(x-3)
We multiply parentheses
5x-4x+12
We add all the numbers together, and all the variables
x+12
Back to the equation:
-(x+12)
x-(x+12)+7=0
We get rid of parentheses
x-x-12+7=0
We add all the numbers together, and all the variables
-5!=0
There is no solution for this equation
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