7(x+1)-8=4+3(1+x)

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Solution for 7(x+1)-8=4+3(1+x) equation: 



7(x+1)-8=4+3(1+x)

We move all terms to the left:

7(x+1)-8-(4+3(1+x))=0

We add all the numbers together, and all the variables

7(x+1)-(4+3(x+1))-8=0

We multiply parentheses

7x-(4+3(x+1))+7-8=0



We calculate terms in parentheses: -(4+3(x+1)), so:

4+3(x+1)

determiningTheFunctionDomain
3(x+1)+4

We multiply parentheses

3x+3+4

We add all the numbers together, and all the variables

3x+7

Back to the equation:

-(3x+7)



We add all the numbers together, and all the variables

7x-(3x+7)-1=0

We get rid of parentheses

7x-3x-7-1=0

We add all the numbers together, and all the variables

4x-8=0

We move all terms containing x to the left, all other terms to the right

4x=8

x=8/4

x=2

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