7(x+1)-8=4x+3(1+x)

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Solution for 7(x+1)-8=4x+3(1+x) equation: 



7(x+1)-8=4x+3(1+x)

We move all terms to the left:

7(x+1)-8-(4x+3(1+x))=0

We add all the numbers together, and all the variables

7(x+1)-(4x+3(x+1))-8=0

We multiply parentheses

7x-(4x+3(x+1))+7-8=0



We calculate terms in parentheses: -(4x+3(x+1)), so:

4x+3(x+1)

We multiply parentheses

4x+3x+3

We add all the numbers together, and all the variables

7x+3

Back to the equation:

-(7x+3)



We add all the numbers together, and all the variables

7x-(7x+3)-1=0

We get rid of parentheses

7x-7x-3-1=0

We add all the numbers together, and all the variables

-4!=0

There is no solution for this equation

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