7(x+1)=3(x+4)

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Solution for 7(x+1)=3(x+4) equation: 



7(x+1)=3(x+4)

We move all terms to the left:

7(x+1)-(3(x+4))=0

We multiply parentheses

7x-(3(x+4))+7=0



We calculate terms in parentheses: -(3(x+4)), so:

3(x+4)

We multiply parentheses

3x+12

Back to the equation:

-(3x+12)



We get rid of parentheses

7x-3x-12+7=0

We add all the numbers together, and all the variables

4x-5=0

We move all terms containing x to the left, all other terms to the right

4x=5

x=5/4

x=1+1/4

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