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7(x+1)=4(10-x)
We move all terms to the left:
7(x+1)-(4(10-x))=0
We add all the numbers together, and all the variables
7(x+1)-(4(-1x+10))=0
We multiply parentheses
7x-(4(-1x+10))+7=0
We calculate terms in parentheses: -(4(-1x+10)), so:We get rid of parentheses
4(-1x+10)
We multiply parentheses
-4x+40
Back to the equation:
-(-4x+40)
7x+4x-40+7=0
We add all the numbers together, and all the variables
11x-33=0
We move all terms containing x to the left, all other terms to the right
11x=33
x=33/11
x=3
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