7(x+1)=4(x-3+x)

Solution for 7(x+1)=4(x-3+x) equation:

7(x+1)=4(x-3+x)

We move all terms to the left:

7(x+1)-(4(x-3+x))=0

We add all the numbers together, and all the variables

7(x+1)-(4(2x-3))=0

We multiply parentheses

7x-(4(2x-3))+7=0


We calculate terms in parentheses: -(4(2x-3)), so:

4(2x-3)

We multiply parentheses

8x-12

Back to the equation:

-(8x-12)


We get rid of parentheses

7x-8x+12+7=0

We add all the numbers together, and all the variables

-1x+19=0

We move all terms containing x to the left, all other terms to the right

-x=-19

x=-19/-1

x=+19