7(x+1)=8x+7-2(3x+4)

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Solution for 7(x+1)=8x+7-2(3x+4) equation: 



7(x+1)=8x+7-2(3x+4)

We move all terms to the left:

7(x+1)-(8x+7-2(3x+4))=0

We multiply parentheses

7x-(8x+7-2(3x+4))+7=0



We calculate terms in parentheses: -(8x+7-2(3x+4)), so:

8x+7-2(3x+4)

determiningTheFunctionDomain
8x-2(3x+4)+7

We multiply parentheses

8x-6x-8+7

We add all the numbers together, and all the variables

2x-1

Back to the equation:

-(2x-1)



We get rid of parentheses

7x-2x+1+7=0

We add all the numbers together, and all the variables

5x+8=0

We move all terms containing x to the left, all other terms to the right

5x=-8

x=-8/5

x=-1+3/5

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