7(x+10)+x=3(x+3)+4

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Solution for 7(x+10)+x=3(x+3)+4 equation: 



7(x+10)+x=3(x+3)+4

We move all terms to the left:

7(x+10)+x-(3(x+3)+4)=0

We add all the numbers together, and all the variables

x+7(x+10)-(3(x+3)+4)=0

We multiply parentheses

x+7x-(3(x+3)+4)+70=0



We calculate terms in parentheses: -(3(x+3)+4), so:

3(x+3)+4

We multiply parentheses

3x+9+4

We add all the numbers together, and all the variables

3x+13

Back to the equation:

-(3x+13)



We add all the numbers together, and all the variables

8x-(3x+13)+70=0

We get rid of parentheses

8x-3x-13+70=0

We add all the numbers together, and all the variables

5x+57=0

We move all terms containing x to the left, all other terms to the right

5x=-57

x=-57/5

x=-11+2/5

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