7(x+12)-3(x-4)-x=2(x+5)+46

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Solution for 7(x+12)-3(x-4)-x=2(x+5)+46 equation: 



7(x+12)-3(x-4)-x=2(x+5)+46

We move all terms to the left:

7(x+12)-3(x-4)-x-(2(x+5)+46)=0

We add all the numbers together, and all the variables

-1x+7(x+12)-3(x-4)-(2(x+5)+46)=0

We multiply parentheses

-1x+7x-3x-(2(x+5)+46)+84+12=0



We calculate terms in parentheses: -(2(x+5)+46), so:

2(x+5)+46

We multiply parentheses

2x+10+46

We add all the numbers together, and all the variables

2x+56

Back to the equation:

-(2x+56)



We add all the numbers together, and all the variables

3x-(2x+56)+96=0

We get rid of parentheses

3x-2x-56+96=0

We add all the numbers together, and all the variables

x+40=0

We move all terms containing x to the left, all other terms to the right

x=-40

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